- Two dice are rolled. What is the probability that their sum is an even number?
A
1/2
B
1/4
C
3/4
D
2/3
Answer and explanation
Correct Answer: A — 1/2
Sum is even if both dice show even or both show odd. P(even)=(1/21/2)+(1/21/2)=1/4+1/4=1/2.
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16 practice sets · Page 1 of 1
1/2
1/4
3/4
2/3
Sum is even if both dice show even or both show odd. P(even)=(1/21/2)+(1/21/2)=1/4+1/4=1/2.
1/2
1/3
1/6
2/3
Composite numbers on a die = {4,6}. Probability = 2/6 = 1/3.
1/2
1/4
3/4
2/3
The product is even if at least one die shows an even number. Probability(even) = 1 - P(both odd). P(both odd)= (3/6)*(3/6)=1/4. So required = 1-1/4=3/4.
1/2
1/3
2/3
1/6
Odd numbers = {1,3,5}. Probability = 3/6 = 1/2.
1/4
1/3
1/6
1/2
Even numbers = {2,4,6}. Probability for one die = 3/6 = 1/2. For two dice = (1/2)*(1/2)=1/4.
1/6
1/12
1/9
1/18
Sums less than 5 are {2,3,4}. Favorable pairs = 1+2+3=6. Probability = 6/36 = 1/6.
1/6
5/6
1/3
2/3
Total outcomes = 6. Not 5 means 5 outcomes. Probability = 5/6.
1/6
1/12
1/18
1/36
Pairs for sum 11 are {(5,6),(6,5)}. Favorable = 2, total = 36. Probability = 2/36 = 1/18.
1/2
2/3
1/3
5/6
Numbers greater than 2 are {3,4,5,6}. Probability = 4/6 = 2/3.
1/2
1/3
2/3
1/6
Multiples of 3 on a die are {3, 6}. Probability = 2/6 = 1/3.
1/6
1/12
1/18
1/36
Doublets are {(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)}. Favorable = 6, total = 36. Probability = 6/36 = 1/6.
1/6
1/12
1/18
1/9
Pairs for sum 7 are {(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)}. Favorable = 6, total = 36. Probability = 6/36 = 1/6.
1/3
1/6
2/3
1/2
Numbers less than 3 are {1, 2}. Probability = 2/6 = 1/3.
1/2
1/3
2/3
1/6
Prime numbers on a die are {2, 3, 5}. Probability = 3/6 = 1/2.
1/2
1/3
2/3
1/6
Even numbers on a die are {2, 4, 6}. Probability = 3/6 = 1/2.
1/2
1/3
1/4
2/3
Numbers greater than 4 on a die are {5, 6}. So favorable outcomes = 2, total outcomes = 6. Probability = 2/6 = 1/3.