Fibonacci Search in Data Structure And Algorithm : Practice MCQ Questions & Answers with Explanations

Since the size of the step is sqrt(n), the complexity is also obviously O(sqrt(n)).

If the step size is 1, it becomes a linear search, if it is n, we reach the end of the list in just on step, if it is n/2, it becomes similar to binary search, therefore the most efficient step size is found to be sqrt(n).

When the speed of access depends on the location previously accessed, Fibonacci search is better compared to binary search as it performs well on those locations which have lower dispersion. Fibonacci search won't work on unsorted arrays. The input should be a sorted array or array should be sorted before Fibonacci search.

Since it divides the array into two parts, although not equal, its time complexity is O(logn), it is better than binary search in case of large arrays.

None.

With every iteration, we divide the given array into two sub arrays(not necessarily equal).