Two resistors of 4 Ω and 6 Ω are connected in parallel across a 12 V supply. What is the total current drawn from the supply?
1.2 A
2 A
5 A
3 A
Correct Answer: C — 5 A
Explanation:
Current through 4 Ω: I1=12/4=3I_1 = 12/4 = 3I1=12/4=3 A. Current through 6 Ω: I2=12/6=2I_2 = 12/6 = 2I2=12/6=2 A. Total: I=3+2=5I = 3 + 2 = 5I=3+2=5 A.
