If the radius of the Earth were doubled (mass unchanged), what would happen to the value of g (acceleration due to gravity) at the surface?
g would double
g would remain the same
g would become one-fourth
g would halve
(C) g would become one-fourth
Explanation:
g=GM/R2g = GM/R^2g=GM/R2. If R doubles, ggg becomes GM/(2R)2=g/4GM/(2R)^2 = g/4GM/(2R)2=g/4. So g becomes one-fourth.
