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For a hamming code of parity bit m=8, what is the total bits - Practice - ObjectiveMcq

For a hamming code of parity bit m=8, what is the total bits and data bits?

Correct Answer: A — (255, 247)

Total bits = 2^m - 1 = 2^8 - 1 = 255. Data bits = 2^m - m - 1 = 256 - 8 - 1 = 247. So the answer is (255, 247).

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