What is the total resistance when three resistors of 2Ω2\Omega2Ω, 3Ω3\Omega3Ω, and 5Ω5\Omega5Ω are connected in series?
5Ω5\Omega5Ω
8Ω8\Omega8Ω
10Ω10\Omega10Ω
15Ω15\Omega15Ω
Correct Answer: C — 10Ω10\Omega10Ω
Explanation:
In a series circuit, total resistance is the sum of individual resistances. 2Ω+3Ω+5Ω=10Ω2\Omega + 3\Omega + 5\Omega = 10\Omega2Ω+3Ω+5Ω=10Ω.