KMnO4KMnO_4KMnO4 reacts with oxalic acid according to the equation 2MnO4- + 5C2O42- + 16H+ -> 2Mn2+ +10CO2 + 8H2O , Here 20 mL of 0.1 M KMnO4KMnO_4KMnO4 is equivalent to
50 mL of 0.5 M C2H2O4C_2H_2O_4C2H2O4
20 mL of 0.1 M C2H2O4C_2H_2O_4C2H2O4
20 mL of 0.5 M C2H2O4C_2H_2O_4C2H2O4
50 mL of 0.1 M C2H2O4C_2H_2O_4C2H2O4
(D) 50 mL of 0.1 M C2H2O4C_2H_2O_4C2H2O4
Explanation:
