For a hamming code of parity bit m=8, what is the total bits and data bits?
(255, 247)
(127, 119)
(31, 26)
(0, 8)
(A) (255, 247)
Explanation:
Total bits = 2^m - 1 = 2^8 - 1 = 255. Data bits = 2^m - m - 1 = 256 - 8 - 1 = 247. So the answer is (255, 247).
