A current of 3 A is flowing through a conductor placed in a magnetic field of strength 0.5 T. If the length of the conductor is 2 m, what will be the force on the conductor?
3 N
1.5 N
6 N
0.5 N
Correct Answer: A — 3 N
Explanation:
The force on the conductor is given by F=B×I×LF = B \times I \times LF=B×I×L.
F=0.5×3×2=3F = 0.5 \times 3 \times 2 = 3F=0.5×3×2=3 N
